Module 8 Test Tube Number Chemistry Lab Report
Module 8 Test Tube Number Chemistry Lab Report
7 attachmentsSlide 1 of 7
- attachment_1attachment_1
- attachment_2attachment_2
- attachment_3attachment_3
- attachment_4attachment_4
- attachment_5attachment_5
- attachment_6attachment_6
- attachment_7attachment_7
UNFORMATTED ATTACHMENT PREVIEW
Module 8 - Chemical Equilibrium: Finding a Constant, Kc MODULE 8 : FINDING AN EQUILIBRIUM CONSTANT POST-LAB ASSIGNMENT 1. Write the Kc expression for the reaction in the Data and Calculation table below. 2. Calculate the initial concentration of Fe3+, based on the dilution that results from adding KSCN solution and water to the original 0.0020 M Fe(NO3)3 solution. See Step 2 of the procedure for the volume of each substance used in Trials 1–4. Calculate [Fe3+]i using the equation: [Fe3+]i = Fe(NO3)3 mL total mL (0.0020 M) This should be the same for all four test tubes. 3. Calculate the initial concentration of SCN–, based on its dilution by Fe(NO3)3 and water: KSCN mL [SCN–]i = total mL (0.0020 M) In Test Tube 1, [SCN–]i = (2 mL / 10 mL)(0.0020 M) = 0.00040 M. Calculate this for the other three test tubes. 4. [FeSCN2+]eq is calculated
Do you similar assignment and would want someone to complete it for you? Click on the ORDER NOW option to get instant services at essayloop.com
Our Advantages
- Quality Work
- Unlimited Revisions
- Affordable Pricing
- 24/7 Support
- Fast Delivery
Order Now
Get 20% Discount
Get 20% off on your first order